Did you mean to convert | kilocalorie [15 °C] kilocalorie [I.T.] kilocalorie [thermochemical] |
to | foot-pound force |
How many kilocalorie [15 °C] in 1 foot pound? The answer is 0.00032390891784877. We assume you are converting between kilocalorie [15 °C] and foot-pound force. You can view more details on each measurement unit: kilocalorie [15 °C] or foot pound The SI derived unit for energy is the joule. 1 joule is equal to 0.00023890295761862 kilocalorie [15 °C], or 0.73756214927727 foot pound. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between kilocalories and foot pounds. Type in your own numbers in the form to convert the units!
1 kilocalorie [15 °C] to foot pound = 3087.28764 foot pound
2 kilocalorie [15 °C] to foot pound = 6174.57529 foot pound
3 kilocalorie [15 °C] to foot pound = 9261.86293 foot pound
4 kilocalorie [15 °C] to foot pound = 12349.15058 foot pound
5 kilocalorie [15 °C] to foot pound = 15436.43822 foot pound
6 kilocalorie [15 °C] to foot pound = 18523.72587 foot pound
7 kilocalorie [15 °C] to foot pound = 21611.01351 foot pound
8 kilocalorie [15 °C] to foot pound = 24698.30116 foot pound
9 kilocalorie [15 °C] to foot pound = 27785.5888 foot pound
10 kilocalorie [15 °C] to foot pound = 30872.87644 foot pound
You can do the reverse unit conversion from foot pound to kilocalorie [15 °C], or enter any two units below:
In physics, a foot-pound force (symbol ft·lbf or ft·lbf), usually abbreviated to foot-pound, is an Imperial and U.S. customary unit of mechanical work, or energy, although in scientific fields one commonly uses the equivalent metric unit of the joule (J). There are approximately 1.356 J/ft·lbf, or exactly 1.355 817 948 331 400 4 J/ft·lbf.
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